## How To Calculate Materials In Concrete Foundation.

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Using images 1 and 2 above and in a bid to also demystify the raft foundation cost, this article will deal extensively on how to calculate your concrete materials like cement, sand and granite that you will use for the foundation.

Often time concrete are mostly mixed in 1:2:4 ratio, when you see such specificationit simply means one bag of cement to four headpans of sand and eight headpans of granite.

Notice that first number represent a bag of cement which is equivalent to two headpans, hence the sand is taken as four headpanss and the granite represented by 4 in the ratio is taken as eight headpans.

Going by this knowledge it is easy for us to do a very fast calculation at least to be close to what we might need on site.

To do this calculation, add the sum of ratio 1+2+4=7

Calculate the cubic volume of concrete for foundation.

Going by the previous article the total lenght of trench was taken as 65.6m

Height of concrete beam is 1.1m or 1100m from image 2

And width is 0.225m or 225mm

therefore total volume of concrete beams =65.6m x 1.1 x 0.225 =16.236

Now divide 16.236 by the sum of the ratio which is 7

16.236/7=2.31943m3

Taking a constant, the volume of a bag of cement is 0.035m3

Divide 2.31943 by 0.035

=66 bags of cement to do all the concrete beams , however don’t forget that cement and sand will also be used for the blinding before the concrete beams are placed .

For the sand reqd.,multiply 2.31943m3 by 2 to know the volume since it is in ratio of 1:2:4

Therefore volume of sand requires =4.63886m3

If we take volume of a tipper as 3.8m3 then

4.63886/3.8=1 1/2 trip of 5 tons tipper for the concrete beam.

For the granite use the same ratio of 1 bag of cement to 4 headpans of sand to 8 headpans of granite

So for granite reqd, multiply 2.31943m3 by 4 to know the volume since it is in the ratio of 1:2:4

therefore volume of granite requires=9.27772

If we take volume of a tipper as 3.8m3 then,

9.27772/3.8=2 1/2 trips of granite (Disregarding water and and other attending expenses

If one bag cost N1,800, then 66 bags =N118,800

And if one trip of sand is N15,000

then 1 1/2 trips =N22,500

And if one trip of 5 tons of granite=N30,000

then granite cost needed =2 1/2 x N30,000

=N75,000

Total=N118,800 + N22,500 + N75,000

=N216,300

For the german floor or oversite concrete-

Multiply the lenght by breadth by the thickness or width of the plan from image.

Add 3.825 +3.95 +1.375 +1.25+4.975+1.25=16.625

Add 3.825+2.910+3.825=10.560

So multiply the sum for the volume=16.625 x 10.560 x 0.2

=35.112m3

To know the number of cement required divide 35.112 by the sum of the ratio which is 7

=35.112 / 7

=5.016m3

Taking a constant, the volume of a bag of cement which is 0.035m3,

divide 5.016m3 by 0.035

=143 bags of cement for the german floor or oversite concrete.

Apply the steps above for the sand and granite,

For sand,

Multiply 5.016 by 2=10.032, now divide by 3.8m3

=3 trips of 5tons sharp sand

For granite,

multiply 5.016 by 4=20.064, now divide by 3.8m3

=5 1/2 trips of 5 tons granite

So if one bag of cement cost N1800

then 143 bags of cement will cost N1800 x 143 =N257,400

And if one trip of sand cost N15,000

then 3 trips of 5 tons sharp sand =N45,000

And if one trip of 5 tons granite cost =N30,000

then 5 1/2 trips of 5 tons granite =N165,000

So total for concrete excluding other attending materials

=N216,000+257,000+45,000+165,000

TOTAL=N683,400

This is hard to understand I believe but you can still study it by bits.

November 20th, 2014 at 6:19 pm

I really accept the way of calculating materials but I suggest that there is a need of adding percentage for waste as well as shrinkage, since the input in concrete is not equal to output due to shrinkage factor

December 23rd, 2014 at 9:02 am

Your work have given me a solution to my concrete and aggregates estimation problem thanks man.

December 27th, 2014 at 4:07 pm

Pls tell me a building job I am free in Laber rate me